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2x^2-5x+5=-x^2-6x-5
We move all terms to the left:
2x^2-5x+5-(-x^2-6x-5)=0
We get rid of parentheses
2x^2+x^2+6x-5x+5+5=0
We add all the numbers together, and all the variables
3x^2+x+10=0
a = 3; b = 1; c = +10;
Δ = b2-4ac
Δ = 12-4·3·10
Δ = -119
Delta is less than zero, so there is no solution for the equation
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